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Algebra 1 Honors · Lesson 2.3

Inequalities and Compound Statements

How it works

An inequality describes a set of allowed values. Adding or subtracting the same quantity preserves its direction. Multiplying or dividing by a negative number reverses the direction. An AND statement requires both conditions; an OR statement permits either one.

a<b, c<0⟹ac>bca<b,\ c<0\quad\Longrightarrow\quad ac>bc

Worked examples

Example 1

Solve −3x+4<13\displaystyle -3x+4<13.

Subtract 4\displaystyle 4: −3x<9\displaystyle -3x<9. Dividing by −3\displaystyle -3 reverses the sign: x>−3\displaystyle x>-3.

Example 2

Solve −2≤3x+1<10\displaystyle -2\le3x+1<10.

Subtract 1\displaystyle 1 throughout: −3≤3x<9\displaystyle -3\le3x<9. Divide by 3\displaystyle 3: −1≤x<3\displaystyle -1\le x<3.

Problems

Problem 2.3.1

Solve 5−2x≥11\displaystyle 5-2x\ge11.

Show worked solution

−2x≥6\displaystyle -2x\ge6. Divide by −2\displaystyle -2 and reverse the relation: x≤−3\displaystyle x\le-3.

Problem 2.3.2

Solve 2<x+1≤6\displaystyle 2<x+1\le6.

Show worked solution

Subtract 1\displaystyle 1 throughout: 1<x≤5\displaystyle 1<x\le5. The left endpoint is excluded and the right is included.

Problem 2.3.3

The diagram shows an interval. Write it as an inequality and in interval notation.

A blue interval runs from an open endpoint at negative 1 to a filled endpoint at 3.
Endpoint fill indicates whether equality is included.
Show worked solution

The open point at −1\displaystyle -1 is excluded and the filled point at 3\displaystyle 3 is included. The set is −1<x≤3\displaystyle -1<x\le3, or (−1,3]\displaystyle (-1,3].

A blue interval runs from an open endpoint at negative 1 to a filled endpoint at 3. The interval is (−1, 3].
The interval is (−1, 3].

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