Repair a hole
Let for and . Find k for continuity.
- The nearby formula simplifies to .
- The limit at is .
- Set to match that limit.
Precalculus Honors · Study guide
Use the limit definition of continuity, repair removable holes, and interpret a derivative as the limiting slope of secants.
Precalculus Honors · Reading: Demana 10th ed. §§11.1, 11.3–11.4; Stewart 8th ed. §§12.3–12.4
A function is continuous at when is defined, its finite two-sided limit exists, and the limit equals . Repairing a removable hole means assigning the existing limiting value at that input.
A jump or an infinite discontinuity cannot be repaired by changing only one point value. At an endpoint of a closed domain, continuity uses the one-sided limit from within the domain.
The average rate of change from to is for nonzero . If these rates approach a finite common value from both directions, their limit is the derivative at .
For , expanding and canceling gives the difference quotient , whose limit is . This is a preview of differentiation, not a reason to substitute before simplifying.
The function is continuous at , but its left slopes are and right slopes are . There is no finite two-sided derivative there.
Differentiability implies continuity; the converse fails. Use the graph to identify corners and breaks, then use one-sided slopes or limits to justify the conclusion.
Let for and . Find k for continuity.
Find the tangent slope to at using the definition.
No calculator required.
1. Is continuous and differentiable at ? Justify each claim.
It is continuous because both one-sided function limits equal . It is not differentiable because the one-sided slopes are and .
2. For away from , what value of gives continuity?
The nearby expression is , whose limit at is . Assign .
3. Use a difference quotient to find for .
The quotient simplifies to for nonzero . Its limit is . The tangent at is .
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