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Precalculus Honors · Study guide

6.1 · Limits from graphs, tables, and algebra

Separate nearby behavior from a point value, compare one-sided limits, and resolve removable indeterminate forms.

Precalculus Honors · Reading: Demana 10th ed. §11.3; Stewart 8th ed. §§12.1–12.2

Learning objectives

  • Read a two-sided limit from nearby graph behavior.
  • Use both sides of a table for numerical evidence.
  • Simplify a removable limit without changing its original domain.

A limit describes approach, not evaluation

The statement lim⁡x→af(x)=L\displaystyle \lim_{x\to a}f(x)=L concerns outputs near a\displaystyle a, with the input distinct from a\displaystyle a. A missing or different point value does not automatically prevent the limit.

Trace the graph toward the input from both sides. A filled dot tells you the defined point value; the nearby curve tells you the approached height.

lim⁡x→af(x)=L\lim_{x\to a}f(x)=L

One-sided limits must agree

A finite two-sided limit exists exactly when the left and right limits exist and agree. If the branches approach different heights, the two-sided limit does not exist regardless of the point value.

A finite table suggests a trend but does not prove behavior at every nearby input. Combine numerical evidence with a formula or a known graph whenever possible.

Zero over zero asks for more analysis

For (x2−4)/(x−2)\displaystyle (x^2-4)/(x-2) near 2\displaystyle 2, substitution gives the indeterminate form 0/0\displaystyle 0/0. Factoring and canceling for x≠2\displaystyle x\ne2 yields x+2\displaystyle x+2, whose limit is 4\displaystyle 4.

The cancellation does not define the original expression at the excluded point. A limit can exist even when the original function is undefined there.

Worked examples

A removable limit

Evaluate lim⁡x→2(x2−4)/(x−2)\displaystyle \lim_{x\to2}(x^2-4)/(x-2).

  1. Factor x2−4=(x−2)(x+2)\displaystyle x^2-4=(x-2)(x+2).
  2. For x≠2\displaystyle x\ne2, the quotient equals x+2\displaystyle x+2.
  3. The limit is 4\displaystyle 4.

A jump

The left-hand limit at 1\displaystyle 1 is 2\displaystyle 2 and the right-hand limit is 5\displaystyle 5. Does a two-sided limit exist?

  1. Compare the two one-sided values.
  2. They differ.
  3. The two-sided limit does not exist, no matter how the function is defined at 1\displaystyle 1.

Common mistakes

  • Using the point value as the limit without examining nearby behavior.
  • Checking only one side.
  • Treating 0/0 as a numerical answer.

Try it yourself

No calculator required.

1. A graph follows y=x+2\displaystyle y=x+2 except that f(2)=1\displaystyle f(2)=1. Find lim⁡x→2f(x)\displaystyle \lim_{x\to2}f(x) and f(2)\displaystyle f(2).

The line y = x plus 2 has an open circle at (2, 4) and a filled point at (2, 1).
Trace the line toward the target from both sides.
Show worked solution

The nearby line approaches height 4\displaystyle 4 from both sides, so the limit is 4\displaystyle 4. The filled point defines f(2)=1\displaystyle f(2)=1.

The line y = x plus 2 has an open circle at (2, 4) and a filled point at (2, 1). The limit at 2 is 4 while the defined function value is 1.
The limit at 2 is 4 while the defined function value is 1.

2. Evaluate lim⁡x→3x2−9x−3\displaystyle \lim_{x\to3}\frac{x^2-9}{x-3}.

Show worked solution

For x≠3\displaystyle x\ne3, factor and cancel to get x+3\displaystyle x+3. The limit is 6\displaystyle 6.

3. A table gives values near 5\displaystyle 5 from the left of a\displaystyle a and near 7\displaystyle 7 from the right. What does this suggest about the two-sided limit?

Show worked solution

It suggests unequal one-sided limits and therefore no two-sided limit. A finite sample is evidence; exact justification needs the governing graph or formula.

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