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Precalculus Honors · Study guide

3.1 · Polar coordinates, conversions, and curves

Convert between coordinate systems, interpret negative radii, and plot polar curves from their defining equations.

Precalculus Honors · Reading: Demana 10th ed. §§6.4–6.5; Stewart 8th ed. §§8.1–8.2

Learning objectives

  • Convert polar points and equations to rectangular form.
  • Recognize equivalent polar coordinates.
  • Identify a polar curve from its equation and samples.

Coordinates describe a directed radius

Polar coordinates (r,θ)\displaystyle (r,\theta) locate a point by distance and direction. A negative radius plots in the direction opposite the specified angle. Equivalent representations include (r,θ+2πk)\displaystyle (r,\theta+2\pi k) and (−r,θ+π+2πk)\displaystyle (-r,\theta+\pi+2\pi k).

The origin has many angle representations. When converting a nonzero rectangular point, use its quadrant rather than relying on a one-argument arctangent alone.

Use the coordinate identities

The identities are x=rcos⁡θ\displaystyle x=r\cos\theta, y=rsin⁡θ\displaystyle y=r\sin\theta, and r2=x2+y2\displaystyle r^2=x^2+y^2. For a point (2,π/3)\displaystyle (2,\pi/3), they give (1,3)\displaystyle (1,\sqrt{3}).

For r=2cos⁡θ\displaystyle r=2\cos\theta, multiply by r\displaystyle r to obtain r2=2rcos⁡θ\displaystyle r^2=2r\cos\theta, hence x2+y2=2x\displaystyle x^2+y^2=2x. Completing the square identifies a circle centered at (1,0)\displaystyle (1,0) with radius 1\displaystyle 1.

x=rcos⁡θ,y=rsin⁡θx=r\cos\theta,\quad y=r\sin\theta

Plot samples and symmetry before naming a curve

Equations such as r=acos⁡(nθ)\displaystyle r=a\cos(n\theta) generate roses, but radius signs affect which direction each point lies. Evaluate several angles and inspect symmetry rather than treating r\displaystyle r as a rectangular height.

A zero radius marks the pole. A sketch should reflect the actual equation and interval; a curve may be traced multiple times as the angle runs through a full revolution.

Worked examples

Convert a point

Convert (4,π/6)\displaystyle (4,\pi/6) to rectangular coordinates.

  1. Use x=4cos⁡(π/6)=23\displaystyle x=4\cos(\pi/6)=2\sqrt{3}.
  2. Use y=4sin⁡(π/6)=2\displaystyle y=4\sin(\pi/6)=2.
  3. The rectangular point is (23,2)\displaystyle (2\sqrt{3},2).

Recognize a circle

Convert r=2cos⁡θ\displaystyle r=2\cos\theta to a rectangular equation.

  1. Multiply by r\displaystyle r to get r2=2rcos⁡θ\displaystyle r^2=2r\cos\theta.
  2. This is x2+y2=2x\displaystyle x^2+y^2=2x.
  3. The completed-square form is (x−1)2+y2=1\displaystyle (x-1)^2+y^2=1.

Common mistakes

  • Plotting a negative radius in the positive direction.
  • Losing the quadrant during rectangular-to-polar conversion.
  • Treating a polar equation as a rectangular function.

Try it yourself

No calculator required.

1. Identify the curve r=2cos⁡θ\displaystyle r=2\cos\theta and give its center and radius.

The polar curve forms a circle to the right of the origin.
Convert the equation using x = r cos theta and r squared = x squared plus y squared.
Show worked solution

Conversion gives (x−1)2+y2=1\displaystyle (x-1)^2+y^2=1. It is a circle with center (1,0)\displaystyle (1,0) and radius 1\displaystyle 1.

The polar curve forms a circle to the right of the origin. The circle has center (1, 0) and radius 1.
The circle has center (1, 0) and radius 1.

2. Convert the polar point (2,π/3)\displaystyle (2,\pi/3) to rectangular coordinates.

Show worked solution

The coordinates are (2cos⁡(π/3),2sin⁡(π/3))=(1,3)\displaystyle (2\cos(\pi/3),2\sin(\pi/3))=(1,\sqrt{3}).

3. Give a positive-radius representation of (−3,π/4)\displaystyle (-3,\pi/4).

Show worked solution

Reverse the direction by adding π\displaystyle \pi: (3,5π/4)\displaystyle (3,5\pi/4) represents the same point.

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