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Precalculus Honors · Study guide

3.3 · Vectors, dot products, and parametric curves

Connect components with magnitude and direction, use dot products for angles, and retain orientation when eliminating a parameter.

Precalculus Honors · Reading: Demana 10th ed. §§6.1–6.3; Stewart 8th ed. §§8.4–8.6

Learning objectives

  • Compute vector magnitudes, sums, and dot products.
  • Use a dot product to test perpendicularity.
  • Eliminate a parameter while retaining the original restrictions and direction.

Components describe a directed displacement

For a vector ⟨a,b⟩\displaystyle \langle a,b\rangle, magnitude is a2+b2\displaystyle \sqrt{a^2+b^2}. Addition and scalar multiplication act on components. A unit vector in its direction is the original vector divided by its nonzero magnitude.

Two equal vectors can have different starting locations. A component diagram distinguishes a vector’s direction and length from the position of an endpoint.

The dot product compares directions

For u=⟨a,b⟩\displaystyle u=\langle a,b\rangle and v=⟨c,d⟩\displaystyle v=\langle c,d\rangle, the dot product is ac+bd\displaystyle ac+bd. For nonzero vectors it also equals ∣u∣∣v∣cos⁡θ\displaystyle |u||v|\cos\theta. A zero dot product therefore identifies perpendicular vectors.

The zero vector is orthogonal in the algebraic sense but has no defined direction angle. Check nonzero magnitudes before dividing to solve for an angle.

u⋅v=∣u∣∣v∣cos⁡θu\cdot v=|u||v|\cos\theta

Parametric equations retain a time or path variable

For x=t+1\displaystyle x=t+1, y=t2\displaystyle y=t^2, eliminate t\displaystyle t using t=x−1\displaystyle t=x-1 to obtain y=(x−1)2\displaystyle y=(x-1)^2. The original parameter interval may describe only part of this parabola.

Elimination alone does not preserve orientation. Record how points move as t\displaystyle t increases, and translate any restrictions on t\displaystyle t into restrictions on the rectangular curve.

Worked examples

Perpendicular vectors

Are u=⟨3,4⟩\displaystyle u=\langle3,4\rangle and v=⟨4,−3⟩\displaystyle v=\langle4,-3\rangle perpendicular?

  1. The dot product is 12−12=0\displaystyle 12-12=0.
  2. Both vectors have nonzero magnitude 5\displaystyle 5.
  3. They are perpendicular.

A restricted parametric curve

Eliminate t\displaystyle t for x=t+1\displaystyle x=t+1, y=t2\displaystyle y=t^2, 0≤t≤2\displaystyle 0\leq t\leq2.

  1. Substitute t=x−1\displaystyle t=x-1.
  2. The equation is y=(x−1)2\displaystyle y=(x-1)^2 with 1≤x≤3\displaystyle 1\leq x\leq3.
  3. As t\displaystyle t increases, the curve moves from (1,0)\displaystyle (1,0) to (3,4)\displaystyle (3,4).

Common mistakes

  • Using a vector’s endpoint coordinates as its components when its tail is not the origin.
  • Dividing by a zero magnitude in the angle formula.
  • Dropping a parameter interval or direction after elimination.

Try it yourself

No calculator required.

1. For u=⟨3,4⟩\displaystyle u=\langle3,4\rangle and v=⟨4,−3⟩\displaystyle v=\langle4,-3\rangle, find both magnitudes, the dot product, and the angle between them.

Vectors (3, 4) and (4, minus 3) start at the origin.
Use components for magnitudes and the dot product.
Show worked solution

Both magnitudes are 5\displaystyle 5. The dot product is 0\displaystyle 0, so the angle is π/2\displaystyle \pi/2.

Vectors (3, 4) and (4, minus 3) start at the origin. Both magnitudes are 5 and their dot product is zero, so they are perpendicular.
Both magnitudes are 5 and their dot product is zero, so they are perpendicular.

2. Find a unit vector in the direction of ⟨3,4⟩\displaystyle \langle3,4\rangle.

Show worked solution

The magnitude is 5\displaystyle 5. Divide each component by it to obtain ⟨3/5,4/5⟩\displaystyle \langle3/5,4/5\rangle.

3. For x=t+1\displaystyle x=t+1, y=t2\displaystyle y=t^2, 0≤t≤2\displaystyle 0\leq t\leq2, give a rectangular equation, restrictions, and direction.

Show worked solution

The equation is y=(x−1)2\displaystyle y=(x-1)^2 on 1≤x≤3\displaystyle 1\leq x\leq3. It is traced from (1,0)\displaystyle (1,0) toward (3,4)\displaystyle (3,4) as t\displaystyle t increases.

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