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Precalculus Honors · Study guide

4.3 · Arithmetic and geometric sequences and series

Distinguish constant differences from constant ratios, index sequences consistently, and test geometric-series convergence.

Precalculus Honors · Reading: Demana 10th ed. §§9.3–9.4; Stewart 8th ed. §§11.1–11.3

Learning objectives

  • Write arithmetic and geometric sequence formulas.
  • Compute finite sums with consistent indexing.
  • Determine when an infinite geometric series converges.

A sequence is a function on integer inputs

An arithmetic sequence has constant difference d\displaystyle d and formula an=a1+(n−1)d\displaystyle a_n=a_1+(n-1)d. A geometric sequence has constant ratio r\displaystyle r and formula an=a1rn−1\displaystyle a_n=a_1r^{n-1}.

The indexing convention matters. If the starting value is labeled a0\displaystyle a_0, the exponent or offset changes. Compare the formula at the stated first index before using it.

A series adds the sequence terms

The finite arithmetic sum is n(a1+an)/2\displaystyle n(a_1+a_n)/2. For a geometric sequence with r≠1\displaystyle r\ne1, the sum is a1(1−rn)/(1−r)\displaystyle a_1(1-r^n)/(1-r). If r=1\displaystyle r=1, simply add n\displaystyle n identical terms.

Summation notation specifies both a rule and an index interval. Count the included terms before applying a closed form; an upper index does not always equal the number of terms.

An infinite geometric series needs a shrinking ratio

If ∣r∣<1\displaystyle |r|<1, the geometric partial sums approach a1/(1−r)\displaystyle a_1/(1-r). If ∣r∣≥1\displaystyle |r|\geq1 and the first term is nonzero, the infinite geometric series does not converge.

A sequence approaching zero is necessary for a series to converge but is not sufficient in general. The finite geometric formula remains valid even when an infinite sum is not.

S∞=a11−r,∣r∣<1S_{\infty}=\frac{a_1}{1-r},\qquad |r|<1

Worked examples

An arithmetic term

Find the tenth term when a1=3\displaystyle a_1=3 and d=4\displaystyle d=4.

  1. Use a10=3+9(4)\displaystyle a_{10}=3+9(4).
  2. The value is 39\displaystyle 39.
  3. The offset is nine intervals from the first to the tenth term.

An infinite geometric sum

Find the sum 3+3/2+3/4+⋯\displaystyle 3+3/2+3/4+\cdots.

  1. The ratio is 1/2\displaystyle 1/2, whose magnitude is less than one.
  2. Use a1/(1−r)\displaystyle a_1/(1-r).
  3. The sum is 6\displaystyle 6.

Common mistakes

  • Using n rather than n minus one with a first-term formula.
  • Applying an infinite-sum formula to a nonconvergent ratio.
  • Confusing a sequence term with a partial sum.

Try it yourself

No calculator required.

1. For the geometric sequence an=3(1/2)n−1\displaystyle a_n=3(1/2)^{n-1}, give the first four terms and the infinite-series sum.

The first terms of 3 times one half to the power n minus 1 decrease toward zero.
Sequence inputs are integers; do not connect them as a continuous function.
Show worked solution

The terms are 3,3/2,3/4,3/8\displaystyle 3,3/2,3/4,3/8. Since ∣r∣=1/2<1\displaystyle |r|=1/2<1, the infinite sum is 3/(1−1/2)=6\displaystyle 3/(1-1/2)=6.

The first terms of 3 times one half to the power n minus 1 decrease toward zero. The first four terms are 3, 3/2, 3/4, and 3/8; the infinite geometric sum is 6.
The first four terms are 3, 3/2, 3/4, and 3/8; the infinite geometric sum is 6.

2. Find the tenth term and the sum of the first ten terms for a1=3\displaystyle a_1=3, d=4\displaystyle d=4.

Show worked solution

The tenth term is 39\displaystyle 39. The sum is 10(3+39)/2=210\displaystyle 10(3+39)/2=210.

3. Does 2+4+8+⋯\displaystyle 2+4+8+\cdots have a finite sum?

Show worked solution

No. Its geometric ratio is 2\displaystyle 2, whose magnitude exceeds one. Its terms do not even approach zero, so the series diverges.

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