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Precalculus · Lesson 6.1

Fundamental Identities

How it works

An identity holds for all inputs where both sides are defined. Rewrite using sine and cosine, use the Pythagorean identity, and keep original domain exclusions even when an expression simplifies.

sin⁡2x+cos⁡2x=1,1+tan⁡2x=sec⁡2x\sin^2x+\cos^2x=1,\quad1+\tan^2x=\sec^2x

Worked examples

Example 1

Simplify 1−cos⁡2x\displaystyle 1-\cos^2x.

The Pythagorean identity gives sin⁡2x\displaystyle \sin^2x.

Example 2

Simplify (1−cos⁡2x)/sin⁡x\displaystyle (1-\cos^2x)/\sin x and state its restriction.

The numerator is sin⁡2x\displaystyle \sin^2x, so the expression equals sin⁡x\displaystyle \sin x where sin⁡x≠0\displaystyle \sin x\ne0.

Problems

Problem 6.1.1

Simplify sec⁡2x−tan⁡2x\displaystyle \sec^2x-\tan^2x.

Show worked solution

The identity 1+tan⁡2x=sec⁡2x\displaystyle 1+\tan^2x=\sec^2x gives 1\displaystyle 1, with cos⁡x≠0\displaystyle \cos x\ne0 retained.

Problem 6.1.2

If sin⁡x=3/5\displaystyle \sin x=3/5 and x is in quadrant II, find cosine.

Show worked solution

cos⁡2x=1−9/25=16/25\displaystyle \cos^2x=1-9/25=16/25. Quadrant II gives cos⁡x=−4/5\displaystyle \cos x=-4/5.

Problem 6.1.3

Show that tan⁡xcos⁡x=sin⁡x\displaystyle \tan x\cos x=\sin x and state the original restriction.

Show worked solution

Replace tangent by sin⁡x/cos⁡x\displaystyle \sin x/\cos x and cancel. The original expression requires cos⁡x≠0\displaystyle \cos x\ne0.

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