Unit 8 · Topics 8.7, 8.8. Original AP Calculus AB notes, worked example, and self-check.
Understand the idea
A solid volume is the integral of its cross-sectional area. First identify the base length from the region, then convert that length to the area of the stated shape. For a semicircle whose diameter is the base width s, area is πs2/8. For an equilateral triangle it is 3s2/4. Rectangular sections require the given height relationship.
V=∫abA(x)dx;Asquare=s2,Asemicircle=8πs2
Worked example
A solid has base between y=x and the axis on 0≤x≤2. Sections perpendicular to the x-axis are squares. Find its volume.
The vertical base width is s=x. A square section has area x2, so V=∫02x2dx=8/3 cubic units.
Try it yourself
Use semicircles with the same base widths instead of squares. Find the volume.
Show solution and reasoning
A(x)=πx2/8, so V=(π/8)(8/3)=π/3. The width is the diameter, not the radius.