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Code Scholars Tutoring · AP Calculus AB

Known cross-section volumes

Unit 8 · Topics 8.7, 8.8. Original AP Calculus AB notes, worked example, and self-check.

Understand the idea

A solid volume is the integral of its cross-sectional area. First identify the base length from the region, then convert that length to the area of the stated shape. For a semicircle whose diameter is the base width s\displaystyle s, area is πs2/8\displaystyle \pi s^2/8. For an equilateral triangle it is 3s2/4\displaystyle \sqrt3s^2/4. Rectangular sections require the given height relationship.

V=∫abA(x) dx;Asquare=s2,Asemicircle=πs28V=\int_a^b A(x)\,dx;\qquad A_{\text{square}}=s^2,\quad A_{\text{semicircle}}=\frac{\pi s^2}8

Worked example

A solid has base between y=x\displaystyle y=x and the axis on 0≤x≤2\displaystyle 0\le x\le2. Sections perpendicular to the x\displaystyle x-axis are squares. Find its volume.

The vertical base width is s=x\displaystyle s=x. A square section has area x2\displaystyle x^2, so V=∫02x2 dx=8/3\displaystyle V=\int_0^2x^2\,dx=8/3 cubic units.

Try it yourself

Use semicircles with the same base widths instead of squares. Find the volume.

Show solution and reasoning

A(x)=πx2/8\displaystyle A(x)=\pi x^2/8, so V=(π/8)(8/3)=π/3\displaystyle V=(\pi/8)(8/3)=\pi/3. The width is the diameter, not the radius.