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Geometry Honors · Lesson 3.2

Similarity and Proportion

How it works

Similar triangles have equal corresponding angles and a common positive ratio between corresponding side lengths. AA, SAS similarity, and SSS similarity establish similarity. Areas scale by the square of the length factor.

a2a1=k,A2A1=k2\frac{a_2}{a_1}=k,\quad\frac{A_2}{A_1}=k^2

Worked examples

Example 1

A triangle with sides 3,4,5\displaystyle 3,4,5 is enlarged by factor 2\displaystyle 2. Find its sides and area scale factor.

The sides are 6,8,10\displaystyle 6,8,10. The area scale factor is 22=4\displaystyle 2^2=4.

Example 2

A 1.5\displaystyle 1.5 m person casts a 2\displaystyle 2 m shadow; a tree casts an 8\displaystyle 8 m shadow at the same time. Find the tree height.

Similar right triangles give h/8=1.5/2\displaystyle h/8=1.5/2. Thus h=6\displaystyle h=6 m, assuming level ground and parallel sunlight.

Problems

Problem 3.2.1

Similar triangles have corresponding sides 3\displaystyle 3 and 9\displaystyle 9. If the smaller area is 6\displaystyle 6, find the larger area.

A small and large similar right triangle with corresponding sides 3 and 9; the small area is 6.
The corresponding length ratio is 9 to 3.
Show worked solution

The length factor is 9/3=3\displaystyle 9/3=3. The area factor is 9\displaystyle 9, so the larger area is 54\displaystyle 54.

A small and large similar right triangle with corresponding sides 3 and 9; the small area is 6. The solution adds labeled relationships.
The length factor is 3, so the larger area is 6 times 9 = 54.

Problem 3.2.2

Triangles have angles 40∘,60∘,80∘\displaystyle 40^\circ,60^\circ,80^\circ and 60∘,80∘,40∘\displaystyle 60^\circ,80^\circ,40^\circ. Are they similar?

Show worked solution

Yes, by AA. Correspondence must match equal angles, regardless of the order given.

Problem 3.2.3

A map uses 1\displaystyle 1 cm for 4\displaystyle 4 km. What real distance corresponds to 7.5\displaystyle 7.5 cm?

Show worked solution

Multiply by the scale: 7.5⋅4=30\displaystyle 7.5\cdot4=30 km.

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