Skip to main content

Precalculus · Lesson 7.3

Inverse Trigonometric Functions

How it works

Inverse trigonometric functions return principal angles in restricted ranges. Arcsine returns angles from minus pi/2 to pi/2, arccosine from zero to pi, and arctangent from minus pi/2 to pi/2 excluding endpoints. They do not undo a trig function on every real angle.

arcsin⁡:[−1,1]→[−π/2,π/2]\arcsin:[-1,1]\to[-\pi/2,\pi/2]

Worked examples

Example 1

Evaluate arcsin⁡(1/2)\displaystyle \arcsin(1/2).

The principal angle is π/6\displaystyle \pi/6.

Example 2

Evaluate arccos⁡(−1/2)\displaystyle \arccos(-1/2).

The value in [0,π]\displaystyle [0,\pi] is 2π/3\displaystyle 2\pi/3.

Problems

Problem 7.3.1

Evaluate arcsin⁡(sin⁡(5π/6))\displaystyle \arcsin(\sin(5\pi/6)).

Show worked solution

Sine is 1/2\displaystyle 1/2, so the principal inverse is π/6\displaystyle \pi/6, not 5π/6\displaystyle 5\pi/6.

Problem 7.3.2

Evaluate arctan⁡(−1)\displaystyle \arctan(-1).

Show worked solution

The principal value is −π/4\displaystyle -\pi/4.

Problem 7.3.3

Find cos⁡(arcsin⁡(3/5))\displaystyle \cos(\arcsin(3/5)).

Show worked solution

The inverse sine angle is in quadrant I, so cosine is the positive value 4/5\displaystyle 4/5.

Need help with this topic?

Work through questions with a tutor and get help with the steps you find difficult.

Get help with this topic