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Geometry Honors · Lesson 1.3

Writing a Proof

How it works

A proof connects each claim to a given fact, a definition, or a proved theorem. State the relevant hypotheses before applying a result. A diagram suggests relationships but does not prove unmarked equalities.

AB=BC, AB+BC=AC ⇒ AC=2ABAB=BC,\ AB+BC=AC\ \Rightarrow\ AC=2AB

Worked examples

Example 1

Given that B\displaystyle B is the midpoint of AC\displaystyle AC, prove AC=2AB\displaystyle AC=2AB.

The midpoint definition gives AB=BC\displaystyle AB=BC. Segment addition gives AC=AB+BC\displaystyle AC=AB+BC. Substitute BC=AB\displaystyle BC=AB to obtain AC=2AB\displaystyle AC=2AB.

Example 2

Two angles form a linear pair and are congruent. Prove each is right.

Their sum is 180∘\displaystyle 180^\circ. Let each measure be x\displaystyle x. Then 2x=180∘\displaystyle 2x=180^\circ, so x=90∘\displaystyle x=90^\circ.

Problems

Problem 1.3.1

Given AB=CD\displaystyle AB=CD and CD=2EF\displaystyle CD=2EF, prove AB=2EF\displaystyle AB=2EF.

Show worked solution

Substitute 2EF\displaystyle 2EF for CD\displaystyle CD in AB=CD\displaystyle AB=CD. This is the substitution property of equality.

Problem 1.3.2

Given m∠A+m∠B=90∘\displaystyle m\angle A+m\angle B=90^\circ and m∠A=35∘\displaystyle m\angle A=35^\circ, prove m∠B=55∘\displaystyle m\angle B=55^\circ.

Show worked solution

Substitute 35∘\displaystyle 35^\circ and subtract from both sides: m∠B=90∘−35∘=55∘\displaystyle m\angle B=90^\circ-35^\circ=55^\circ.

Problem 1.3.3

Why is a segment appearing horizontal insufficient to prove it perpendicular to a segment that appears vertical?

Show worked solution

A sketch can be distorted. Use a right-angle marking, perpendicularity as a given, or slopes whose product is −1\displaystyle -1 when both slopes exist.

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