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AP Precalculus · Lesson 2.3

Rescaling the Exponent

How it works

An exponent counts how many growth periods have elapsed. If a quantity doubles every d time units, use time divided by d. Equivalent models can express the same growth with different time units or bases.

P(t)=P0bt/d=P0(b1/d)tP(t)=P_0b^{t/d}=P_0\left(b^{1/d}\right)^t

Worked examples

Example 1

A quantity doubles every 3\displaystyle 3 hours from an initial 10\displaystyle 10. Give a model and its value after 6\displaystyle 6 hours.

P(t)=10⋅2t/3\displaystyle P(t)=10\cdot2^{t/3}; P(6)=40\displaystyle P(6)=40.

Example 2

A substance halves every 5\displaystyle 5 days from an initial 80\displaystyle 80 g. Find the mass after 10\displaystyle 10 days.

M(t)=80(1/2)t/5\displaystyle M(t)=80(1/2)^{t/5}, so M(10)=20\displaystyle M(10)=20 g.

Problems

Problem 2.3.1

A quantity starts at 12\displaystyle 12 and triples every 2\displaystyle 2 days. Find its value after 4\displaystyle 4 days.

Show worked solution

P(t)=12⋅3t/2\displaystyle P(t)=12\cdot3^{t/2}, so P(4)=108\displaystyle P(4)=108.

Problem 2.3.2

Rewrite 100⋅4t/2\displaystyle 100\cdot4^{t/2} using a per-unit base.

Show worked solution

Because 41/2=2\displaystyle 4^{1/2}=2, the equivalent model is 100⋅2t\displaystyle 100\cdot2^t.

Problem 2.3.3

A model uses t\displaystyle t in years: P(t)=50(1.08)t\displaystyle P(t)=50(1.08)^t. Rewrite using months m.

Show worked solution

Substitute t=m/12\displaystyle t=m/12: P(m)=50(1.08)m/12\displaystyle P(m)=50(1.08)^{m/12}. The monthly factor is (1.08)1/12\displaystyle (1.08)^{1/12}.

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