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Geometry Honors · Lesson 6.3

Compositions

How it works

Apply coordinate transformations in the stated order. Function composition acts from right to left. Reversing a translation and a reflection can change the image, so show the intermediate point.

(F∘T)(P)=F(T(P))(F\circ T)(P)=F(T(P))

Worked examples

Example 1

Translate (1,2)\displaystyle (1,2) by (3,0)\displaystyle (3,0), then reflect across the y\displaystyle y-axis.

Translation gives (4,2)\displaystyle (4,2); reflection gives (−4,2)\displaystyle (-4,2).

Example 2

Reverse the operations in the preceding example.

Reflection first gives (−1,2)\displaystyle (-1,2); translation then gives (2,2)\displaystyle (2,2). The results differ.

Problems

Problem 6.3.1

Apply a 90∘\displaystyle 90^\circ counterclockwise rotation about the origin twice to (3,1)\displaystyle (3,1).

Show worked solution

First (−1,3)\displaystyle (-1,3), then (−3,−1)\displaystyle (-3,-1). The composition is a 180∘\displaystyle 180^\circ rotation.

Problem 6.3.2

Reflect (2,5)\displaystyle (2,5) across the x\displaystyle x-axis and then the y\displaystyle y-axis.

Show worked solution

The intermediate point is (2,−5)\displaystyle (2,-5) and the final point is (−2,−5)\displaystyle (-2,-5).

Problem 6.3.3

Translate a point by (4,−2)\displaystyle (4,-2) and then by (−1,5)\displaystyle (-1,5). Give the single equivalent translation.

Show worked solution

Add displacement vectors: (3,3)\displaystyle (3,3).

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