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Precalculus Honors · Study guide

2.2 · Trigonometric graphs, inverses, and periodic models

Read amplitude, period, phase shift, and midline; use principal inverse-trigonometric ranges correctly.

Precalculus Honors · Reading: Demana 10th ed. §§4.4–4.8; Stewart 8th ed. §§5.3–5.5, 6.4

Learning objectives

  • Identify sinusoidal graph parameters.
  • Build a periodic model from extrema and period.
  • Evaluate inverse trigonometric expressions using their principal ranges.

Separate amplitude, midline, and period

For y=Asin⁡(B(x−C))+D\displaystyle y=A\sin(B(x-C))+D, the amplitude is ∣A∣\displaystyle |A|, midline is y=D\displaystyle y=D, period is 2π/∣B∣\displaystyle 2\pi/|B|, and phase shift is C\displaystyle C. Factor the input before reading the shift.

Maximum and minimum heights determine the midline as their average and amplitude as half their difference. The horizontal distance between consecutive peaks gives the period.

T=2π∣B∣T=\frac{2\pi}{|B|}

Read tangent and reciprocal-function restrictions

Tangent has period π\displaystyle \pi and vertical asymptotes where cosine is zero. Secant and cosecant have branches separated by zeros of cosine or sine. Their ranges exclude values strictly between −1\displaystyle -1 and 1\displaystyle 1 before transformations.

A graphing window can hide asymptotes or suggest false connecting segments. Use the defining denominator zeros to confirm the domain and branch breaks.

An inverse function needs a restricted range

The principal range of arcsin⁡\displaystyle \arcsin is [−π/2,π/2]\displaystyle [-\pi/2,\pi/2], of arccos⁡\displaystyle \arccos is [0,π]\displaystyle [0,\pi], and of arctan⁡\displaystyle \arctan is (−π/2,π/2)\displaystyle (-\pi/2,\pi/2). These restrictions make the inverses single-valued.

For arcsin⁡(sin⁡(5π/6))\displaystyle \arcsin(\sin(5\pi/6)), the inner sine is 1/2\displaystyle 1/2 and the principal inverse output is π/6\displaystyle \pi/6, not 5π/6\displaystyle 5\pi/6. An inverse symbol does not cancel indiscriminately outside the restricted interval.

Worked examples

Read a model

Analyze y=3sin⁡(2(x−π/4))+1\displaystyle y=3\sin(2(x-\pi/4))+1.

  1. Amplitude is 3\displaystyle 3 and midline is y=1\displaystyle y=1.
  2. The period is 2π/2=π\displaystyle 2\pi/2=\pi.
  3. The phase shift is π/4\displaystyle \pi/4 to the right.

Build from extrema

A wave has maximum 8\displaystyle 8, minimum 2\displaystyle 2, period 4\displaystyle 4, and a maximum at time 0\displaystyle 0. Give a cosine model.

  1. The amplitude is (8−2)/2=3\displaystyle (8-2)/2=3 and midline is 5\displaystyle 5.
  2. The angular coefficient is 2π/4=π/2\displaystyle 2\pi/4=\pi/2.
  3. A model is y=3cos⁡(πt/2)+5\displaystyle y=3\cos(\pi t/2)+5.

Common mistakes

  • Reading the period as the inside coefficient.
  • Confusing amplitude with maximum height.
  • Canceling an inverse outside its principal range.

Try it yourself

No calculator required.

1. For y=2sin⁡(2x)+1\displaystyle y=2\sin(2x)+1, find amplitude, period, midline, and range.

The curve 2 sine of 2x plus 1 oscillates about height 1.
Compare a full cycle with the maximum and minimum heights.
Show worked solution

Amplitude is 2\displaystyle 2, period is π\displaystyle \pi, and midline is y=1\displaystyle y=1. The range is [−1,3]\displaystyle [-1,3].

The curve 2 sine of 2x plus 1 oscillates about height 1. Amplitude is 2, period is pi, and the range is from minus 1 to 3.
Amplitude is 2, period is pi, and the range is from minus 1 to 3.

2. Evaluate arcsin⁡(sin⁡(5π/6))\displaystyle \arcsin(\sin(5\pi/6)).

Show worked solution

The sine is 1/2\displaystyle 1/2. The principal arcsine range selects π/6\displaystyle \pi/6.

3. A periodic height has maximum 10\displaystyle 10, minimum 4\displaystyle 4, and period 6\displaystyle 6, starting at its maximum. Give a model.

Show worked solution

Amplitude is 3\displaystyle 3, midline is 7\displaystyle 7, and angular coefficient is π/3\displaystyle \pi/3. A model is h(t)=3cos⁡(πt/3)+7\displaystyle h(t)=3\cos(\pi t/3)+7.

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