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Additional course content; not assessed on the AP Precalculus Exam.

AP Precalculus · Lesson 4.1

Parametric Equations

How it works

Parametric equations express both coordinates in terms of a shared parameter. Eliminating the parameter gives a relation, but the parameter interval and direction must be retained. Different parameterizations can trace the same curve at different speeds.

x=x(t),y=y(t)x=x(t),\quad y=y(t)

Worked examples

Example 1

Eliminate t from x=2t+1\displaystyle x=2t+1, y=t−3\displaystyle y=t-3, for all real t.

Since t=(x−1)/2\displaystyle t=(x-1)/2, y=(x−1)/2−3=(x−7)/2\displaystyle y=(x-1)/2-3=(x-7)/2.

Example 2

For x=cos⁡t\displaystyle x=\cos t, y=sin⁡t\displaystyle y=\sin t, 0≤t≤2π\displaystyle 0\le t\le2\pi, identify the curve and direction.

The unit circle is traced once counterclockwise from (1,0)\displaystyle (1,0).

Problems

Problem 4.1.1

For x=2t\displaystyle x=2t, y=t2\displaystyle y=t^2, 0≤t≤2\displaystyle 0\le t\le2, eliminate t and state the domain and direction.

Parabola segment from 0,0 to 4,4.
Elimination gives y = x squared / 4, with x restricted to [0,4].
Show worked solution

y=x2/4\displaystyle y=x^2/4 for 0≤x≤4\displaystyle 0\le x\le4, traced from (0,0)\displaystyle (0,0) to (4,4)\displaystyle (4,4) as t increases.

Parabola segment from 0,0 to 4,4. The solution adds labeled relationships.
As t increases, the point moves from (0,0) toward (4,4).

Problem 4.1.2

For x=3cos⁡t\displaystyle x=3\cos t, y=2sin⁡t\displaystyle y=2\sin t, eliminate t.

Show worked solution

The identity gives x2/9+y2/4=1\displaystyle x^2/9+y^2/4=1, an ellipse.

Problem 4.1.3

Why does eliminating t from x=t2\displaystyle x=t^2, y=t2\displaystyle y=t^2 not give the entire line y=x\displaystyle y=x?

Show worked solution

The parameter forces x≥0\displaystyle x\ge0, so only the ray with y=x≥0\displaystyle y=x\ge0 is traced.

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